operative?
Also mathematicians use i for imaginary, engineers use j. The story does not add up. I have never seen a single mathematician use j for imaginary.
As an EE, I used both. Def not a mathematician though. Fuck that, I just plug variables into programs now.
Thank you for the belly laugh!
$\int dx f(x)$ is standard notation for physicists
Me, a language/arts person: “Huh?”
Web dev here. “Huh?”
Medical here. “Huh?”
I think rather
d/dx
is the operator. You apply it to an expression to bind free occurrences ofx
in that expression. For example,dx²/dx
is best understood asd/dx (x²)
. The notation would be clear if you implement calculus in a program.If not fraction, why fraction shaped?
If you use exterior calculus notation, with d = exterior derivative, everything makes so much more sense
As a physicist I can’t understand why would anyone complain about a +jb or $\int dx f(x)$. Probably because we don’t fuck
As a software dude I can see you wrote a regex, I just can’t find out what you’re trying to match.
Heeyy… So when you need to express something more, well, delicate than just code, you need to use math symbols. For that you can use tex expressions. Modern markdown supports it: just copy and paste the $…$ part into any render engine
I’m scared. I think I’ll generate some backend spec to calm down.
Nooo… You should write spec and generate code, not the other way around
This is the kind of brat I can get behind. 😏
😏
Is anyone doing anything tonight?
Something something distance calls for norm, not just squares.
||i||² + ||1||² = 2
This one made me laugh almost as much as the OP. Thank you!
Imagining your death. :P
But seriously, it’s perfectly sensible when remember that i is just the mathematical representation of “left turn”, just like -1 is the mathematical representation of “go backwards”-- and as we know, two left turns sends you backwards. So think about this triangle in the following way:
Imagine you are a snail, starting at the origin. Now imagine that you walk forward 1 step along the horizontal line. Then you turn 90° to the left to start walking along the vertical line, but then, because you need to walk i steps along this line you take another 90° turn to the left, which means that you are now walking backwards and you end up back at the origin. How far away from the origin are you? Zero steps.
no, d…do you have a plan?
Better plot than 50 Shades of Grey
hehe plot. getit? math and graphs and shit
Lmfao kill yourself
sado-mathochist
Well done, truly
Fake and gay.
No way the engineer corrects the mathematician for using j instead of i.
Right? They got that shit backwards. Op is a fraud. i is used in pure math, j is used in engineering.
The mathematician also used “operative” instead of, uh, something else, and “associative” instead of “commutative”
As an engineer I fully agree. Engineers¹ aren’t even able to do basic arithmetics. I even cannot count to 10.
¹ Except maybe Electrical engineers. They seem to be quite smart.
Engineer here, I can definitely count to 10 tho
0 1 10
0 1 everything that comes after is simply summarizes as “many”
deleted by creator
10? That’s the name some put to 1e1, right?
Except maybe Electrical engineers.
Yup, I can count just fine to the 10th number in a zero-indexed counting system: black, brown, red, orange, yellow, green, blue, violet, gray, white.
Electrical engineers are the ones that use j though (because i is used for current)
The inner machinations of an electrical engineer is too complicated for me to understand, I think they might be thinking on a higher order to understand these circuits
Thats why I barely passed my electrical engineering class lol
How do we know it’s gay though? OP could be a girl (male)
Newfag.
(sorry! seemed like the appropriate 4chan reply)
Because it’s 4chan. And there are no women on the Internet on 4chan
Sure OP is a girl. Guy In Real Life
My thoughts exactly lol
Wait bottom mathematican is using j=√-1 instead of i and not the engineer? Because I’m EE gang, and all my homies use j.
The fun starts when you study quaternions
i^2 = j^2 = k^2 = ijk = −1
This can’t be real
They’re actually very useful: https://en.wikipedia.org/wiki/Quaternion
(…I think you may have gotten whooshed…)
Hehe, maybe a little, but wanted to share just in case someone didn’t know :3
I clicked your link, I barely made it out of highschool so I have no idea what any of it means, but I like reading things I shouldn’t understand anyway, sometines it’s so interesting even without understanding.
So I thank you!
It gets worse actually. You can define a number system using any power of 2 amount of i-like units in a similar relationship to quaternions using the Cayley-Dickson construction
Fascinatingly, you lose some property of the algebra at each step. Quaternions aren’t commutative: ABC != CBA. Octonians aren’t associative: (AB)C != A(BC). Once you get into 16 i’s with subscripts, it really gets crazy.
(Also, I just got the joke. Damnit @[email protected] your serious answer threw me off!)
Hehe, yeah, the joke was too good :P
this isn’t real
That part also got me really confused. All the mathematicans I know use i while engineers use i or j depending on the kind of engineer. I’ve never seen a Pikachu engineer using anything other than j.
OPs boyfriend is obviously an i engineer and hates j engineers. No one can stay angry at mathematicians - engineers on the other hand…
Pikachu engineer
That’s a fucking favorite now. Keeping that in my back pocket.
I agree. Clearly i is current. What is this i=√-1 nonsense.
a real mathematician would use
(0, 1)
instead ofi
[Lapsed] mechanical engineering gang checking in. I was also surprised. Though, tbh, I think it came down to personal preference of the professor more than field-wide consensus.
NGL, this is hot.
I’m a mechanical engineering student with a math minor and I’m a switch so yeah, I’d take either side of this
Relationship goals
Hum… I don’t think the integral “operator” applies by multiplication.
You can put the dx at the beginning of the integral, but not before it.
Physicists be like: whitness me
Nobody on your link is treating the integral “operator” as multiplicative.
dx \int f(x)
is blatantly different from\int f(x) dx
If you were using nonstandard analysis with dx an infinitesimal you could put it outside I guess. Maybe with differential forms too?
In the context of differential forms, an integral expression isn’t complete without an integral symbol and a differential form to be integrated.
Switch it with a summation operator and see if it makes sense. The problem isn’t the operation by itself, but the fact that the operator implies an argument application, like a function.