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Memory-maker Micron has found a way to keep prices for its products sky-high for another five years, by signing 16 “strategic customer agreements” (SCAs) that include a floor price the company says comes with “a very robust gross margin for Micron, well above our peak quarterly margins in any past cycle.”
Micron CEO, president and chairman Sanjay Mehrotra explained the SCAs in prepared remarks delivered during the company’s Q3 earnings call. He explained that Micron has signed 16 SCAs, most of them covering 2026 to 2030, and that they involve a commitment to buy a certain quantity of product and pay for it in a pricing band that has a floor and a ceiling price. The floor price covers the historically high gross margins mentioned above, and the ceiling price means those who commit to an SCA are insulated if memory prices go even higher.



How the hell does one hide and then use a backdoor in ram?
But did you think about China Bad™?
You add a piece of code that scans for a specific very big prime number and if it finds that, you look for any process and inject into stdlibc any backdoor of your choice
You add a piece of code (to ram, which famously does not hold information while unpowered).
Which scans for a specific very big prime number (finding large primes quickly would completely invalidate the world’s cryptography and therefore banking, that’s why people are afraid of the quantum boogeyman).
You look for any process and inject into stdlibc any backdoor of your choice (just any process, doesn’t need elevated permissions, assuming they use libc, assuming the backdoor hasn’t been patched out from the other end, defeated by any of the dozens of software integrity checks that have become standard).
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could have a chip that looks for a certain sequence of bytes then changes some other bytes as a result… it would probably introduce massive latency though…
Hang on, I’m gonna add a suspicious new component onto a part that is incredibly expensive and heavily scrutinized specifically for speed and latency that will bit bash the I/o.