No. A geometric progression (u_n) with ratio r and first term a satisfies:
For every n, u_n = a × r^n.
Ratio r and first term a are fixed, exponent n varies. The sequence (u_n) does grow (or decrease) exponentially fast.
At least that’s what the English definition is, and in my first language as well. If there is one in which “geometric” means “power function”, I’d actually be curious to know.
At a geometric… rate ?
Pretty common way of expressing exponential growth
https://en.wikipedia.org/wiki/Geometric_progression
Except geometric means the exponent is fixed, i.e.
f(x) = x^2
f(x) = x^3
…
f(x) = x^n
where n is a constant, while exponential means the exponent is the variable, like
f(x) = 3^x
No. A geometric progression (u_n) with ratio r and first term a satisfies:
For every n, u_n = a × r^n.
Ratio r and first term a are fixed, exponent n varies. The sequence (u_n) does grow (or decrease) exponentially fast.
At least that’s what the English definition is, and in my first language as well. If there is one in which “geometric” means “power function”, I’d actually be curious to know.
Username checks out, this guy maths
He’s a terminator, not a mathinator.
Thank god he wasn’t a burninator
Terminator was a man, Or maybe he was a robot-man, Or maybe he was just a robot…
The question is…is he fully functional?
AND anatomically correct?
Aren’t all computers mathinators?
Ask ChatGPT.
Geometric rate is pretty fast. It doesn’t have to be exponential to be scary.